x(2x^2+5)=7+2x^2

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Solution for x(2x^2+5)=7+2x^2 equation:


Simplifying
x(2x2 + 5) = 7 + 2x2

Reorder the terms:
x(5 + 2x2) = 7 + 2x2
(5 * x + 2x2 * x) = 7 + 2x2
(5x + 2x3) = 7 + 2x2

Solving
5x + 2x3 = 7 + 2x2

Solving for variable 'x'.

Reorder the terms:
-7 + 5x + -2x2 + 2x3 = 7 + 2x2 + -7 + -2x2

Reorder the terms:
-7 + 5x + -2x2 + 2x3 = 7 + -7 + 2x2 + -2x2

Combine like terms: 7 + -7 = 0
-7 + 5x + -2x2 + 2x3 = 0 + 2x2 + -2x2
-7 + 5x + -2x2 + 2x3 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-7 + 5x + -2x2 + 2x3 = 0

The solution to this equation could not be determined.

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